Question

Two bodies having masses m = 30 kg and m2 = 40 kg are attached

to the ends of string of negligible mass and suspended from a light

frictionless pulley. Find the acceleration of the body and tension in

the string.​

Answer 1

Answer:

1.42m/sec^2, 342.85N

Explanation:

a = (m2-m1)g/m1+m2

= (40-30) 10/30+40

= 100/70

= 1.42 m/sec^2

T = 2m1m2g/m1+m2

= 2×30×40×10/30+40

= 342.85 N

Answer 2

Answer:

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$Lets \: hover \: at \: the \: scenario, \\ \\ </p><p></p><p>The \: two \: bodies \: are \: at \: the \: two \: ends \: of \: a string \: which \: is \: across \: a \: pulley, \\ \\ one \: with \: heavy \: mass \: will \: move \: downwards \: and \: one \: with \: lower \: mass \: move \: upwards, \\ \\ Let \: the \: tension \: in \: the \: string \: be  \: T, \\ \\ Given, m1=40g,m2=60g \: \\ \\ g=10ms−2 \\ \\ According \: to \: Free \: Body \: Diagram,  \\ \\ T−m1g=m1a \: \\ \\ m2g−T=m2a</p><p></p><p></p><p> \\ \\ a=m1+m2(m2−m1)g</p><p> \\ \\ a=100grams20grams×10ms−2 \\ \\ a=2ms−2</p><p></p><p></p><p></p><p></p><p></p><p></p><p>$