Question

Two bodies having masses
m = 30kg, m,= 40kg are attached in the
ends of a string of neligible mass and
suspended by a light friction less pulley. If
g= 9.8m/s.
The acceleration
of the
system is​

Answer 1

Answer:

a=( M1-M2)/(M1+M2) *g

so

a=(40-30)/(40+30)*9.8

a=(10)/(70)*9.8

a=(98)/(70)

a=1.4 m/s2

therefore

The acceleration

of the

system is​ a=1.4 m/s2

hope it helps