Question

Two bodies of different masses are dropped from heights of 16 m and 25 m
tively. The ratio of the time taken by them is
3) 4:5
4) 16:25
1) 25:16
2) 5:4
in numerically equal to the
merid
velocity​

Answer 1

$\tt\large{\underline{\underline{AnsweƦ :}}}$

Option 3) 4 : 5

$\tt\large{\underline{\underline{Explaination :}}}$

From equation of motion we know that when a body is dropped,

$\sf{h=\dfrac{1}{2}gt²}$

$\sf{So,\: \dfrac{t_1}{t_2} = \sqrt{ \dfrac{h_1}{h_2} } = \sqrt{ \dfrac{16}{25} } = \dfrac{4}{5} }$