Two bodies of different masses m, and m, are
dropped from two different heights a and b. The
ratio of the time taken by the two to cover these
distances are
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S =it + 1/2at^2
Mass has no role in freely falling body.
So,
a = 1/2 × 10 × t^2
b = 1/2 × 10 × T^2
a/b = t^2/T^2
t/T. = √a/b
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