Question

Two bodies of different masses m, and m, are dropped from two different heights, viz a and b. The ratio of times
taken by the two to drop through these distance is​

Answer 1

Answer:

Time is given by √2h/g .

So it is independent of mass .

Ratio will be

$r = \frac{ \sqrt{ \frac{2a}{g} } }{ \sqrt{ \frac{2b}{g} } } = \sqrt{ \frac{a}{b} } \: \: or \: \: \frac{ \sqrt{a} }{ \sqrt{b} }$