Question

Two bodies of different masses m1 and m2 are dropped from different height h1 and h2. The ratio of times taken by the two to drop through these distances is ​

Answer 1

Answer :For a freely falling object :

a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we get h2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =b

so, T1/T2=√a/b

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