two bodies of equal mass moves with uniform velocity of V and 3V respectively find the ratio of their Kinetic energies
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Answered by
4
Answer:
Let the mass of the bodys are m
So the kinetic energy of the 1st body is KE1=(1/2)mv^2
The kinetic energy of the 2nd body is KE2=(1/2)m(3v)^2
=(9/2)mv^2
So the ratio of kinetic energy is
KE1:KE2
=(1/2):(9/2)
=1:9
Answered by
5
HERE IS YOUR ANSWER :-
we have given that mass of two bodies are same
So , mass of the two bodies = m
velocity of body 1 = v
therefore, it's kinetic energy =
1/2(mv²)
velocity of body 2 = 3v
therefore it's kinetic energy =
1/2(9mv²)
Now , ratio of their kinetic energy =
{1/2(mv²)} /{1/2(9mv²)
= 1 : 9
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