Physics, asked by baliharirajbhar6, 9 months ago

two bodies of equal masses are having velocities in the ratio 1:3 find the ratio of their kinetic energies ​

Answers

Answered by abhradip123
1

Answer:

K.E=0.5×m×v

2

K.E(1st)=0.5×m×v

2

K.E(2nd)=0.5×m×(2v)

2

Hence the ratio is 0.5×m×v

2

:0.5×m×(2v)

2

=1:4

Hence the ratio is 1:4.

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Answered by Anonymous
0

hlo ❤️

K.E=0.5×m×v

2

K.E(1st)=0.5×m×v

2

K.E(2nd)=0.5×m×(2v)

2

Hence the ratio is 0.5×m×v

2

:0.5×m×(2v)

2

=1:4

Hence the ratio is 1:4.

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