Question

Two bodies of equal masses are kept at height of h and 2h what will be the ratio of their potential energies?

Answer 1

Heya user.......★★★★★


Their ratio will be

=>mgh/mg*2h

=1:2.

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Hope this will help u

:-)

Answer 2

Hey there!

Mass of first body = Mass of second body

i.e $M_A = M_B$

Heights = h and 2h respectively.

Now,

$\dfrac{P.E_{A}}{P.E_B}\\\\=\dfrac{mgh}{mg2h}\\\\=\dfrac{1}{2}\\\\=1 : 2$

Hope it Helps You!