Question

: two bodies of equal masses are projected upward simultaneously along the two axes a along x axis and b along y axis they are projected with equal velocities 490 cm/s find the separation between the two bodies where B reaches back to starting int once again

Answer 1

Answer:

Hello my friend

Explanation:

Bro refers to the attachment.

Answer 2

Answer:

V

CM

=

m

1

+m

2

m

1

v

1

+m

2

v

2

=(v

1

+v

2

)/2

Initially,U

CM

=40m/s

X

CM

=40/2=20maboveground.

MaximumheightmeansV

CM

=0

Thatis,0

2

−40

2

=2×(−10)×(H−20)

ThusH=100m

Explanation:

100 m is correct