two bodies of equal masses move with uniform velocity is v and 3v respectively find the ratio of thier kinetic energies?
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K.E.=½MV²
K.E.1=½MV²
K.E.2=½M(3V)²
K.E.1/K.E.2=1/9
K.E.1=½MV²
K.E.2=½M(3V)²
K.E.1/K.E.2=1/9
Aami11:
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let,the mass of the bodies=m unit
the kinetic energy of first body=1/2×m×v^2
=mv^2/2
the kinetic energy of second body=1/2×m×(3v)^2=9mv^2/2
the ratio=mv^2/2:9mv^2/2=1:9(ans)
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please mark as brainliest answer if you get from this
the kinetic energy of first body=1/2×m×v^2
=mv^2/2
the kinetic energy of second body=1/2×m×(3v)^2=9mv^2/2
the ratio=mv^2/2:9mv^2/2=1:9(ans)
hope this is the answer
please mark as brainliest answer if you get from this
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