Two bodies of m1 and m2 separated by a distance of 20 m. experience a force of 60N between them. If the distance between them is reduced to 1/3 of previous distance, how much change will be there in the force between them?
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Answer:
F' = 9F
Explanation:
F = G.m₁.m₂ / R²
G - universal gravitational constant
R - distance between the masses
F = G.m₁.m₂ / R²
R' = R/3
F' = G.m₁.m₂ / R'²
F' = G.m₁.m₂ / (R/3)²
F' = G.m₁.m₂ / (R²/9)
F' = 9 [G.m₁.m₂ / R²]
F' = 9F
The force between them increases by a factor of 9
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