two bodies of mass 1 kg and 2kg moving with a velocity aur stopped by that force sem 4 then the ratio of their stopping distance
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Answered by
1
Answer:
type the question proparly
Answered by
1
Explanation:
1:21:2
2:12:1
2–√:12:1
1:2–√1:2
Answer :
A
Solution :
(a) Given m1=1kg,m2=2kgm1=1kg,m2=2kg
Let kinetic energy of bodies be K1K1 and K2K2
For first body, K1=Fs1 ….(i) K1=Fs1 ….(i)
For second body, K2=Fs2 …(ii) K2=Fs2 …(ii)
Dividing Eq. (i) by Wq. (ii), we get
s1s2=K1K2,s1s2=m1v21m2v22s1s2=K1K2,s1s2=m1v12m2v22
Given, v1=v2 So ,s1s2=m1m2,s1s2=12
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