Question

two bodies of mass 1 kg and 2kg moving with a velocity aur stopped by that force sem 4 then the ratio of their stopping distance​

Answer 1

Answer:

type the question proparly

Answer 2

Explanation:

1:21:2

2:12:1

2–√:12:1

1:2–√1:2

Answer :

A

Solution :

(a) Given m1=1kg,m2=2kgm1=1kg,m2=2kg

Let kinetic energy of bodies be K1K1 and K2K2

For first body, K1=Fs1 ….(i) K1=Fs1 ….(i)

For second body, K2=Fs2 …(ii) K2=Fs2 …(ii)

Dividing Eq. (i) by Wq. (ii), we get

s1s2=K1K2,s1s2=m1v21m2v22s1s2=K1K2,s1s2=m1v12m2v22

Given, v1=v2 So ,s1s2=m1m2,s1s2=12