Two bodies of mass 10 and 20 kg are kept on horizontal table and are tied to the strrings a horizontal foce f is applied to it = 600N what is tension in each case
Answers
hi there
here's your answer
hope it helps
Complete question:
Two bodies of masses 10 kg and 20 kg respectively, kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to (i) A (ii) B along the direction of string. What is the tension in the string in each case?
Answer:
(i) The tension if force is applied to A is 400 N.
(ii) The tension if force is applied to B is 200 N.
Given:
Horizontal force = F = 600 N
Mass of body A = m₁ = 10 kg
Mass of body B = m₂ = 20 kg
Explanation:
The total mass of the system is given as:
m = m₁ + m₂ = 10 + 20 = 30 kg
On applying Newton's second law, we get,
F = ma
a = F/m = 600/30 = 20 m/s²
The force applied on the mass A is:
F - T = m₁a
T = F - m₁a
On substituting the values, we get,
T = 600 - (10 × 20)
∴ T = 400 N
The force applied on the mass B is:
F - T = m₂a
T = F - m₂a
On substituting the values, we get,
T = 600 - (20 × 20)
∴ T = 200 N