two bodies of mass 100 kg each out of which first 15 metre per second body is in moving condition and second body is at rest are collide obliquely then find out their velocity after collision ?
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Answer:
7.5 m/s
Explanation:
m1v1 + m2v2 = ( m1 + m2)v
100×15 + 100×0 = 200v
v = 15/2 = 7.5 m/s
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