Question

Two bodies of mass 1kg & 2kg have acceleration 4m/s² and 2m/s² respectively perpendicular to each other. If in the system of three bodies, third is of mass 4kg, no external force acts on the system than what will be the acceleration of third body?

(please answer)​

Answer 1

Explanation:

The acceleration of CM of the system is given by

a

CM

=

m

2

+m

2

m

1

a

1

+m

2

a

2

CM

=

2+4

2×1+4(−2)

=−1m/s

2

Negative sign indicates that acceleration of CM will be in the direction of acceleration of 4kg mass.