Question

Two bodies of mass 4kg and 6 kg are attached to ends of a string passing over a pulley . The 4 kg mass is stretched to the table top by another string . What is the free body diagram of this question??

Answer 1

T-4g=4a
6g-t=6a
Solving these two equation we get
2g=10a
2*9.8=10a
a=1.96
T1=m*a
Mass=4+6=10kg
and acceleration= 1.96
T1=10*1.96
==>19.6N

Answer 2

Answer:20 N

Explanation:the best way to solve is the difference between the weights of the two blocks

T2= 6×10-4×10=60-40=20N