Question

Two bodies of mass 4kg and 6kg are attached to the ends of a string passing over a pulley. A 4kg mass is attached to the table top by another string. The tension in the string T1 is equal to : ​

Answer 1

Answer:Tension in string connecting the two masses is 60N and that in the string connecting 4kg with table is 20N

Explanation:By drawing FBD for 6kg mass,we find that T1=m1*g=6*10=60N.

Similarly by drawing FBD for 4kg mass, we get T(between 4kg mass and table)=T1-40=60-40=20N.

HOPE IT HELPS.

Answer 2

Answer:

Explanation:

m1 = 2kg

m2= 3kg

Now,

T= (2m1 × m2 / m1 × m2 )g

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a = (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5