Question

Two bodies of mass 50 kg and 120 kg are kept at 10 m distant apart.Find the gravitational force between them. G =6.67*10-11 n-m2/kg2​

Answer 1

Answer:-

$hence \: the \: answer \: is \: 4.002 \times {10}^{ - 9} newton$

Explanation:

$mass(m1) = 50 \: kg \\ mass(m2) = 120 \: kg \\ distance \: between \: them(r) = 10 \: m</p><p>$

We know that

F = G (m1 . m2)/r²

$6.67 \times {10}^{ - 11} \times \frac{50 \times 120}{ {10}^{2} } \\ = 6.67 \times {10}^{ - 11} \times \frac{6 000}{100} \\ = 6.67 \times {10}^{ - 11} \times 60 \\ = 4.002 \times {10}^{ - 9} \: newton$