Question

two bodies of mass 6 kg and 4kg are tied to the string in the table is MOD and the pulley frictionless then acceleration of mass 6 kg will be ji equal to 10 MS square ​

Answer 1

Answer:

Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up

So the equation of net force on 6kg is given as

6×10−T=6a

equation of net force on 4kg is given as

T−4×10=4a

now add the above two equations

6×10−(4×10)=(6+4)×a

60 - 40 = 10a

a = 2m/s

2

So 6 kg will accelerate downwards while 4 kg will accelerate upwards

with acceleration 2 m/s

2

now in order to find the tension force

T−4×10=4×2

T = 48N

So the tension in the string is 48 N

Explanation:

Hope it helps you