Two bodies of mass m1 and m2 have same kinetic energy the ratio of their momentum is
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let E be the kinetic energy of the two bodies
then their momentums are √2m1E and √2m2E respectively
then ratio of their momentums=(√m1)/(√m2)
I.e. √m1 : √m2
then their momentums are √2m1E and √2m2E respectively
then ratio of their momentums=(√m1)/(√m2)
I.e. √m1 : √m2
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Given: Two bodies of mass m₁ and m₂ have same kinetic energy.
To find: the ratio of their momentum.
Solution: We know by the relationship between kinetic energy and momentum that:
K.E. = p²/ 2m _____(1)
We use the above relation to find the ratio of their momentum.
Kinetic energies of the masses are equal implying:
K.E.₁ = K.E.₂ = K.E. _____(2)
From (1) and (2) and as per the question:
K.E.₁ = K.E.₂
p₁²/ 2m₁ = p₂²/ 2m₂
p₁²/ p₂² = m₁ / m₂
p₁ / p₂ = √m₁ / √m₂
Hence, the ratio of the momentum is √m₁ : √m₂.
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