Physics, asked by chaudhariraj109, 6 months ago

Two bodies of masses 0.03 kg, and 0.04 kg,
are tied to the ends of a massless string. This
string passes over the frictionless pulley. The
tension in the string is​

Answers

Answered by ParagKulkarni
0

Explanation:

Referring figure,

0.04g−T=0.04a

and

T−0.03g=0.03a

∴0.04g−(0.03a+0.03g)=0.04a

a=1.4

T=0.03×1.4+0.03×9.8

=0.336N

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