Two bodies of masses 0.03 kg, and 0.04 kg,
are tied to the ends of a massless string. This
string passes over the frictionless pulley. The
tension in the string is
Answers
Answered by
0
Explanation:
Referring figure,
0.04g−T=0.04a
and
T−0.03g=0.03a
∴0.04g−(0.03a+0.03g)=0.04a
a=1.4
T=0.03×1.4+0.03×9.8
=0.336N
mark as brainliest
Similar questions