Question

Two bodies of masses 0.03 kg, and 0.04 kg,
are tied to the ends of a massless string. This
string passes over the frictionless pulley. The
tension in the string is​

Answer 1

0.04g−T=0.04a

and  

T−0.03g=0.03a

∴0.04g−(0.03a+0.03g)=0.04a

a=1.4

T=0.03×1.4+0.03×9.8

 =0.336N

Answer 2

ANSWER
Fg
2
​
−Fg
1
​
=(0.03+0.04)a (0.04kg mass is more likely to fall)
(9.8)(0.04)−(9.8)(0.03)=0.07a
a=1.4m/s
2


for tension:

Fg
2
​
−T=0.04∗1.4
T=0.336N
ANSWER
Fg
2
​
−Fg
1
​
=(0.03+0.04)a (0.04kg mass is more likely to fall)
(9.8)(0.04)−(9.8)(0.03)=0.07a
a=1.4m/s
2


for tension:

Fg
2
​
−T=0.04∗1.4
T=0.336N
ANSWER
Fg
2
​
−Fg
1
​
=(0.03+0.04)a (0.04kg mass is more likely to fall)
(9.8)(0.04)−(9.8)(0.03)=0.07a
a=1.4m/s
2


for tension:

Fg
2
​
−T=0.04∗1.4
T=0.336N