Question

two bodies of masses 0.5 kg and 1 kg are lying in xy plane at minus (-1, 2) and (3 4 ).respectively what are the coordinates of the centre of mass​

Answer 1

Answer:

(5/3,10/3)

Explanation:

:;since X co-ordinate of c.m = x1m1+x2m2/m1+m2........similarly for y co-ordinate

Answer 2

The position of center of mass is (5/3, 10/3).

Explanation:

Given that,

Mass of body 1, $m_1=0.5\ kg$

Mass of body 2, $m_2=1\ kg$

These two bodies are placed in xy plane (-1, 2) and (3 4) respectively. The position of center of mass is given by :

$C=(\dfrac{m_1x_1+m_2x_2}{m_1+m_2}, \dfrac{m_1y_1+m_2y_2}{m_1+m_2})\\\\C=(\dfrac{0.5\times (-1)+1\times 3}{0.5+1}, \dfrac{0.5\times 2+1\times 4}{0.5+1})\\\\C=(\dfrac{5}{3},\dfrac{10}{3})$

So, the position of center of mass is (5/3, 10/3). Hence, this is the required solution.

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