Two bodies of masses 1 kg and 2 kg are attached to the ends of a 2 m long weightless rod. This system
is rotating about an axis passing through the middle point of rod and perpendicular to length. Calculate the M.I. of system.
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Explanation:
m1=1kg and m2=2kg
r1=r2=1m
since for multiple mass system
I=m1r1²+m2r2²
I=1×1²+2×1²
I=3kgm²
hope it helps you
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