Question

Two bodies of masses 1 kg and 2 kg moving with same
velocities are stopped by the same force. Then the
ratio of their stopping distances is:​

Answer 1

Explanation:

2kg mass will require more force....

Answer 2

Answer:

1/2

Explanation:

let a force f1 be applied on mass1 1 kg

and

f2 be applied on mass2 2 kg

Given : f1 = f2

Let Initial velocity be u and final velocity is zero for both

f1= f2

m1.a1 = m2.a2

(1)a1 = (2)a2 - -(1)

Wkt, v^2 — u^2 = 2as

For m1 => 0 — u^2 = 2(a1)s1

s1 =—u^2/2a1

From (1) => s1 =—u^2/2(2a2)--(2)

For m1 => 0 — u^2 = 2(a2)s2

s2 =—u^2/2a2--(3)

(2)/(3) => s1/s2 = 1/2

PLZ MARK BRAINLIEST