two bodies of masses 100 kg and 10,000 kg are at a distance 1 m apart. at which point on the line joining them a third body experiences the net gravitational force zero
Answers
Answered by
2
Explanation:
Let x be the distance from 100㎏ for which resultant gravitational intensity is zero, gravitational force due to 100㎏ is equal and opposite to 10,000㎏. So,
x
2
G×100
=
(1−x)
2
G×10000
100x
2
=(1−x)
2
10x=1−x
x=
11
1
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