Question

Two bodies of masses 10kg and 20kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force of 600N is applied to (i) A, (ii) B along the direction of string. What is the tension in the string in each case? Please some send the diagram.​

Answer 1

Answer:

sorry bro photo is not clear ....

in 1st case tension will be = 520

in 2nd case tension will be = 410

if g=10

Answer 2

Answer:

Given,

Mass of body (m1) = 10 Kg

Mass of body (m2) = 20 Kg

Horizontal force F = 600 N

Let a is the acceleration of system

(A) when force F applied on A:

use free body diagram ,

For body m1 ,

F - T = m1a ______________(1)

For body m2 ,

T = m2a ___________(2)

Solve eqns (1) and (2)

a = F/(m1 + m2)

= 600/(10 + 20)

= 20 m/s²

And T = m2a = 20×20 = 400 N

(B) again, using free body diagram when force on B

For body m1 ,

T = m1a _____________(1)

For body B,

F - T = m2a ___________(2)

Solve eqns (1) and (2)

a = F/(m1 + m2)

= 600/(10+20)

= 30 m/s²

And T = 10×20 = 200 N

Explanation: