Physics, asked by chingkheielangbam6, 4 days ago

two bodies of masses 10kg and 25 kg Safa force of 5 Newton and 10 Newton respectively find acceleration in both case​

Answers

Answered by VELINENI
0

Answer:

formula :-force =mass ×acceleration

a=f/m

case-1

a=5/10

a=0.5m/s^2

case-2

a=10/25

a=2/5

a=0.4m/s^2

Answered by Johnsonmijo
2

Answer:

The acceleration of the bodies is 0.5 m/s² and 0.4 m/s² respectively.

Explanation:

We know the equation of force, F = ma

From this, the acceleration can be found as, a = F / m

Body 1

Mass of the body, m = 10 Kg

Force acting on the body, F = 5 N

∴ acceleration of the body, a = F / m

                                              a = 5 / 10

                                              a = 0.5 m/s²

Body 2

Mass of the body, m = 25 Kg

Force acting on the body, F = 10

∴ Acceleration of the body, a = F / m

                                              a = 10 / 25

                                              a = 0.4 m/s²

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