two bodies of masses 10kg and 25 kg Safa force of 5 Newton and 10 Newton respectively find acceleration in both case
Answers
Answered by
0
Answer:
formula :-force =mass ×acceleration
a=f/m
case-1
a=5/10
a=0.5m/s^2
case-2
a=10/25
a=2/5
a=0.4m/s^2
Answered by
2
Answer:
The acceleration of the bodies is 0.5 m/s² and 0.4 m/s² respectively.
Explanation:
We know the equation of force, F = ma
From this, the acceleration can be found as, a = F / m
Body 1
Mass of the body, m = 10 Kg
Force acting on the body, F = 5 N
∴ acceleration of the body, a = F / m
a = 5 / 10
a = 0.5 m/s²
Body 2
Mass of the body, m = 25 Kg
Force acting on the body, F = 10
∴ Acceleration of the body, a = F / m
a = 10 / 25
a = 0.4 m/s²
Similar questions