Question

two bodies of masses 10kg and 2kg are moving with the velocity 2Î-7j+3k and -10î+35j-3k find the velocity of centre of mass?​

Answer 1

Answer:

2k

Explanation:

Velocity of centre of mass is given by

V = (m1v1 + m2v2)/(m1 + m2)

= (10(2i - 7j + 3k) + 2(-10i + 35j - 3k))/(10 + 2)

= (20i - 70j + 30k - 20i + 70j - 6k)/12

= 24k / 12

= 2k

Answer 2

Answer:

The velocity of center of mass is 2k m/s.

Explanation:

Given that,

Mass $m_{1}=10\ kg$

Mass $m_{2}=2\ kg$

Velocity of first body $v_{1}=2i-7j+3k$

Velocity of second body $v_{2}=-10i+35j-3k$

We need to calculate the velocity of center of mass

Using formula of center of mass

$v_{cm}=\dfrac{m_{1}v_{1}+m_{2}v_{2}}{m_{1}+m_{2}}$

Put the value into the formula

$v_{cm}=\dfrac{10\times(2i-7j+3k)+2\times(-10i+35j-3k)}{10+2}$

$v_{cm}=\dfrac{20i-70j+30k-20i+70j-6k}{12}$

$v_{cm}=\dfrac{24k}{12}$

$v_{cm}=2k\ m/s$

Hence, The velocity of center of mass is 2k m/s.