Question

two bodies of masses 15 kg and 10 kg are connected with a light string kept on a smooth surface mounted force f is equal to 500 newton is applied to A 15 kg as shown in the figure the tension acting in the string​

Answer 1

ANSWER
Horizontal force,F=600 N
Mass of body A, m
1
​
=10 kg
Mass of body B, m2=20 kg
Total mass of the system, m=m1+m2=30 kg
Using Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:
F=ma
a=
m
F
​
=
30
600
​
=20m/s
2

When force F is applied on body A:
The equation of motion can be written as: F−T=m
1
​
a
T=F−(m
1
​
)a
=600−10×20=400 N (i)

When force F is applied on body B:
The equation of motion can be written as:
F−T=m
2
​
a
T=F−(m
2
​
)a
T=600−20×20=200 N (ii)
which is different from value of T in case (i). Hence our answer depends on which mass end, the force is applied.