Question

Two bodies of masses 1kg & 2kg are released from same height one on moon and other on earth, find ratio of time's taken to reach surface
(A) 1:3
(B) 76:1
(C) 1:1
(D) 1:6

Answer 1

Answer:

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Answer 2

The ratio of time taken to reach the surface of the moon and earth is 1:6.

Given:-

Mass of first body (m1) = 1kg

Mass of second body (m2) = 2kg

To Find:-

The ratio of time taken to reach the surface of the moon and earth.

Solution:-

We can simply find out the ratio of time taken to reach the surface of the moon and earth by using the following methods.

As

Mass of first body (m1) = 1kg

Mass of second body (m2) = 2kg

Time taken to reach the surface (t) =?

g (moon) = 1/6 of g (earth)

Let the height be h

According to the formula,

$t = \sqrt{\frac{2h}{g} }$

Here, height is the same for both the surfaces

So,

$t \infty \sqrt{ \frac{1}{g} }$

$\frac{te}{tm} = \sqrt{ \frac{gm}{ge} }$

$({\frac{te}{tm} })^{2} = \frac{g}{6g}$

$({\frac{te}{tm} })^{2} = \frac{1}{6}$

Hence, The ratio of time taken to reach the surface of the moon and earth is 1:6.

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