Two bodies of masses 250g and 500g moving in the direction opposite to each other with a speed of 2 m/s collide and stick together after collision. Find the velocity of the combined mass after the collision.
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Explanation:
Given : m1=2kg m2=1kg u1=3 m/s u2=4 m/s
Let the common velocity of the combined body be V
Mass of combined body M=2+1=3kg
Applying conservation of momentum :
2×3−1×4=3×V ⟹V=32 m/s
Momentum of the system P=2×3−1×4=2 kg m/s
Loss in kinetic energy of the system due to collision ΔK.E=K.Ei−K.Ef
ΔK.E=21(2)×32+21(1)×42−21(3)×(32)2
⟹ΔK.E=349 J
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Answer:
answer is 349 joules
Explanation:
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