two bodies of masses 2kg and 3kg are hung to the ends of a string passing over a smooth pulley at the end of 5 seconds the string breaks. How much higher the 2kg mass will go?
Answers
Answered by
5
M1 = 2kg
m2= 3kg
Now,
T=>
= (2m1 × m2 / m1 × m2 )g
= (2 ×2 ×3/ 2+3 )g
= 12/5 g
a =>
= (m2 - m1 / m1+ m2) g
= (3-2/3+2)g
= g/5
Geniusgirl27:
hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
Similar questions