Question

two bodies of masses 2kg and 3kg are hung to the ends of a string passing over a smooth pulley at the end of 5 seconds the string breaks. How much higher the 2kg mass will go?

Answer 1

M1 = 2kg

m2= 3kg

Now,

T=>

= (2m1 × m2 / m1 × m2 )g

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a =>

= (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5