Question

two bodies of masses 2kg and 3kg fall from height 10 and 12 m find ratio of: a)time of following b). ratio of the velocity striking to the earth​

Answer 1

Answer:

a) Ratio of time of flights is  $t_1:t_2=\sqrt{5}:\sqrt{6}$

b)Ratio of velocities is $v_1:v_2=\sqrt{5}:\sqrt{6}$

Explanation:

m1 = 2kg

m2 = 3kg

Mass m1 falls from the height , h1 = 10 m

Mass m2 falls from the height , h2 = 12 m

a) Time of flight, $t=\sqrt{\frac{2h}{g}}$

  Time of flight is independent of mass.

  Time of flight is proportional to the square root of h.

  $\frac{t_1}{t_2}=\sqrt{\frac{h_1}{h_2}}$$=\sqrt{\frac{10}{12}}=\frac{\sqrt{5}}{\sqrt{6}}$

 $t_1:t_2=\sqrt{5}:\sqrt{6}$

b)Velocity , v= u +gt = 0 + gt = gt

    Velocity is directly proportional to time of flight.

      $\frac{v_1}{v_2}=\frac{t_1}{t_2}=\frac{\sqrt{5}}{\sqrt{6}}$

      $v_1:v_2=\sqrt{5}:\sqrt{6}$