Question

two bodies of masses 2m and M have their kinetic energy in the ratio 8 is to 1 then the ratio of their linear momentum is

please tell me guys​

Answer 1

Explanation:

K.E. = mv^2/2

K.E. for two diff. mass M and 2M :

(2Mv1^2/2) / (Mv2^2 /2) = 8/1

(2v1^2)/(v2^2) = 8/1

v1^2 / v2^2 = 4/1

v1/v2 = 2/1

then ratio of momentum :

= 2Mv1 : Mv2

= 4:1

Answer 2

2 8:1

=>1 = 2;2=

=>1:2= 8:1

=>= √2 .

=>1/2=√1/2.1/.2

=>√2/ 8/1

=>1:2= 4:1