Question

Two bodies of masses 4 kg and 5 kg are acted upon by the same force if the acceleration of the lighter body is 3 m / s ^2 then find the acceleration produced in heavier body. what will be the acceleration if that greater force is applied on both the bodies tied together

Answer 1

4*3=12 N

as the force is same

so

if they are tied together so they will behave as a single body

9*X=12

X=1.33

Answer 2

✦ANSWER

Let. mass of lighter body = m(1)

Let mass of heavy body = m(2)

Acceleration of the lighter. body =
$3m {s}^{ - 2}$

✦GIVEN

m(1)=4kg

m(2)=5kg

$a(1) = 3 m {s}^{ -2}$



✦PART 1 ☞



so The force which produce an acceleration in

lighter body

$f = m(1)a(1)$


$f = 4 \times 3 = 12 \: newton$


F= 12N





Now acceleration produced in heavier body
is equal. to force produce in lighter body


$f(2) = f(1)$

$= > f(2) = 12 \: newton$



so acceleration in heavier body is


$f(2) = m(2) \times a(2)$


$12 = 5 \times a(2)$


$a(2) = \frac{12}{5}$


$a(2) = 2.4m {s}^{ - 2}$



✦PART 2 ☞


NOW greater force is applied on the mass tied together .

the acceleration is equal to


$= > a(sum \: \: ofmasses \: ) = f(2)$



$= a(m(1) + m(2)) = 12$




$a(4 + 5) = 12$



$a = \frac{12}{9}$


$a = 1.33m {s}^{ - 2}$