Two bodies of masses 4 kg and 6 kg are attached to the ends of a string passing
over a pulley. The 4 kg mass is attached to the table top by another string. The
tension in this string T, is equal to (Take g = 10 ms?)
т
4Kg.
6Kg
A) 20N
T
B) 251
10 CD
10N
Answers
EXPLANATION.
=> Two bodies of masses 4kg and 6kg are
attached to the ends of a string passing
over a pulley.
=> The 4 kg mass is attached to the table Top
by another string.
To find the tension in the string.
=> For a 6 kg of block
=> T = 6g
=> T = 60 N ........(1)
=> For a 4 kg of block
=> T - T¹ - 4g = 0
=> T = T¹ + 4g
=> 60 = T¹ + 40
=> T¹ = 60 - 40
=> T¹ = 20N
Therefore,
option [ A ] is correct answer.
Question :
Two bodies of masses 4 kg and 6 kg are attached to the ends of a string passing over a pulley. The 4 kg mass is attached to the table top by another string. The tension in this string T, is equal to ( Take g = 10 m/s² )
A) 20 N
B) 25 N
C) 30 N
D) 35 N
Solution :
Apply FBD for 6 kg block ,
Apply FBD for 4 kg block ,
So , Tension in the string = 20 N
Option A
Cheers :) Best of Luck :)