two bodies of masses 4 kgs and 6 kgs are suspended freely and passing over a frictionless Pulley with the help of mass less rope. the tension in the rope is??
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4 kg block will move upwards as 6kg block is heavy.So acceleration of block 4kg is upwards and 6kg is downwards.
The first eq is T-4g=4a
2nd eq is 6g-T=6a
Adding both
2g=10a(g=9.8 or 10)
2(9.8)=10a
a=1.96 m/s² or 2 m/s²
Put value of a in eq 1
T-40=4(2)
T=48N
The first eq is T-4g=4a
2nd eq is 6g-T=6a
Adding both
2g=10a(g=9.8 or 10)
2(9.8)=10a
a=1.96 m/s² or 2 m/s²
Put value of a in eq 1
T-40=4(2)
T=48N
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Hey
This is the answer to your question.
Hope it helps #))
This is the answer to your question.
Hope it helps #))
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