Question

Two bodies of masses 40 kg and 10 kg are separated 3
m apart. Calculate the position of a point in between
them when the net gravitational intensity due to both
of them is zero.​

Answer 1

Let the distance from the mass 10 kg be 'd' m

And the mass from 40 Kg be (3-d) m

$\boxed{Gravitational\: field\: intensity = \dfrac{GM}{R^{2}}}$

Since Net Gravitational Intensity is 0, then Intensity if both masses is equal.

$\dfrac{G\times 10}{d^{2} } = \dfrac{G\times 40}{(3-d^{2})}$

10/d² = 40/(3-d)²

(3-d)² = 4d²

3(d² + 2d - 3) = 0

d² + 3d - d - 3 = 0

d(d+3) -1 (d+3) = 0

d = 1

d = -3 (rejected)

Therefore distance of point from mass 10 kg = 1 m

And from mass 40 kg = 2 m

Answer 2

Answer:

Explanation:

I don't know