Question

Two bodies of masses 5kg and 4kg are acted upon by the same force if the acceleration of lighter body is 2 metre per second square then the acceleration of heavier body is

Answer 1

Given,m=4 kg,S1=5m,S2=2m

Distance traveled in nth second S=u+1/2a(2n-1)

S1=5=u+1/2a(2(1)-1)=u+1/2a_______1

S2=2=u+1/2a(2(3)-1)=u+5/2a———2

From 1 and 2,

We get a=-1.5m/s²,u=3.75m/s

F=ma=4*(-1.5)=-6kN

Answer 2

Force acting on lighter body= m×a                                                 =4×2=8N A/q. Force acting on both mass is same. Thus , a(5 kg mass)= F/m=8/5=1.6ms^2