Chemistry, asked by seershika18, 8 months ago

Two bodies of masses 8 Kg and 2 Kg are separated by a distance of 40m. The force of attraction

between them is __ N [ ]

a) 6.67 × 10–9 b) 6.67 × 10–10 c) 6.67 × 10–11 d) 6.67 × 10–8​

Answers

Answered by i5bvikashgmailcom
0

Answer:

option D

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Answered by khalkaraditya8
4

Answer:

they are not correct option. correct answer is

F=6.67×10^-13

Explanation:

F=Gm1m2/r^2

m1 =8kg

m2=2kg

r=40m

F=G×8×2/(40)^2

F=G16/1600

G is 6.67×10^-11

F=6.67×10^-11/100

F=6.67×10^-13

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