Question

Two bodies of masses 8kg and 32kg are placed at a distance 12m. A third body of mass 5kg is to be placed at such a point that the force acting on this body is zero. Find the position of that point.​

Answer 1

Answer:

Hey mate, here is your Answer!!

Mark me as BRAINLIST!!

Explanation:

$⇢(Diagonal)2=(Length)2+(Breadth)2⇢(BD)2=(BC)2+(CD)2⇢(BD)2=(24cm)2+(7cm)2⇢(BD)2=576cm2+49cm2⇢(BD)2=625cm2⇢BD=625cm2⇢BD=25cm×25cm⇢BD=25cm⎩⎪⎪⎪⎧Diagonal⎭⎪⎪⎪⎫⇢(Diagonal)2=(Length)2+(Breadth)2⇢(BD)2=(BC)2+(CD)2⇢(BD)2=(24cm)2+(7cm)2⇢(BD)2=576cm2+49cm2⇢(BD)2=625cm2⇢BD=625cm2⇢BD=25cm×25cm⇢BD=25cm⎩⎪⎪⎪⎧Diagonal⎭⎪⎪⎪⎫⠀∴Hence, Length of Diagonal is C) 25 cm.∴Hence,LengthofDiagonalisC)25cm.$

Mark me as BRAINLIST!!