Question

Two bodies of masses m 1 = 200g and m 2 = 500g are dropped from a certain height h,
i)How will the value of acceleration due to gravity g 1 and g 2 for m 1 and m 2 respectively differ
from each other ii) Calculate the value of g 1 and g 2 for the two bodies when they reach
a height of h/2.

Answer 1

Answer:

Explanation:

Given:

Two balls A and B of mass m and 2m

Initial velocity of first ball =2V

Initial velocity of second ball= V

1)Compare inertia:

As inertia is measure of mass. Hence the object with greater mass has more mass.

So, Ball B is having more inertia.

2)Compare momentum:

Momentum is the product of mad and velocity.

P= mxv

So Pa=mx2v=2mv

Pb=2mxv=2mv

So, momentum in both the cases are same.

3)The force needed to stop them in same time:

From Newton's second law:

F= dp/dt

= change in monentum/dt

= 0-2mv/time

As momentum is same for given time , so same force is required to stop them.