Two bodies of masses m and 3m is moving with velocities v and 2v respectively. Find (1)
the ratio of their kinetic energies?
Answers
Answer:
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Explanation:
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Answer:
let two bodies of masses ,
body x = m
body y = m ( because they are equal in mass )
given .
body x = v
body y = 2v
k.e. of x = 1/2mv^2
k.e. of y = 1/2m(2v)^2
= \frac{1}{2} *m *4*v^2
2
1
∗m∗4∗v
2
= 2mv^22mv
2
ratio = \frac{K.E.of x}{K.E.of y}
K.E.ofy
K.E.ofx
= \frac{ \frac{1*mv^2}{2} }{2mv^2}
2mv
2
2
1∗mv
2
1:4 or 1/4
Explanation:
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