Question

Two bodies of masses m1 and m2 are moving with equal kinetic energy. the ratio of their linear momentum is

Answer 1

P1sq/P2sq=2*m1*k.e/2*m2*k.e
P1/p2=root(m1/m2)
P=momentum
Hope it helps you
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Answer 2

Hey there!

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$

Then Ratio = √(2m2) : √(2m1)

Hope It Helps You!