Question

two bodies of masses m1 and m2 are separated by a distance d. if F is the force of gravitation, then write down an expression for F . what will be the change in F if -- 1. one of the masses is doubled and the distance is halved. 2.both the masses are tripled and the distance is also three times increased


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Answer 1

Answer:

F= (4 G m1m2)/ (r2) = 4F

Explanation:

According to Universal law of gravitation, the force of attraction between 2 bodies is:-

F = (G m1m2)/r2

Where m1m2 = the masses of the two bodies,

r = distance between them

G = gravitational Constant

When the distance is reduced to half i.e. r’ = (1/2) r then,

F’ = (G m1m2)/r2

= (G m1m2)/(r/2)2

= (4 G m1m2)/ (r2) = 4F

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