Question

Two bodies of masses m1 and m2 have equal kinetic energies.what is the ratio of their linear momentum

Answer 1

Given,
Two bodies m1 and m2
Let the velocity of 1st body be = v1
Then its Kinetic energy = p²/2m1=(m1v1)²/2m2
Let the velocity of 2nd body be = v2
Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2
Now, (m1v1)²/2m1 = (m2v2)²/2m2
 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$
Then Ratio = √(2m2) : √(2m1)

Answer 2

Answer:

Explanation:

Secondary School Physics 8+4 pts

Two bodies of masses m1 and m2 have equal kinetic energies.what is the ratio of their linear momentum

Report by Darkicloutole 21.02.2017

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

Then Ratio = √(2m1) : √(2m2)

Secondary School Physics 8+4 pts

Two bodies of masses m1 and m2 have equal kinetic energies.what is the ratio of their linear momentum

Report by Darkicloutole 21.02.2017

Answers

DwivediramlalaAmbitious

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duragpalsingh

DuragpalsinghMaths AryaBhatta

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m1

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

∴(m1v1)/(m2v2) = \frac{ \sqrt{2m2} }{ \sqrt{2m1} }

Then Ratio = √(2m2) : √(2m1)