Two bodies of masses M1 and M2 have equal kinetic energy what is the ratio of their momentum
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just equate what is given...you'll get it
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Hey there!
Given,
Two bodies m1 and m2
Let the velocity of 1st body be = v1
Then its Kinetic energy = p²/2m1=(m1v1)²/2m2
Let the velocity of 2nd body be = v2
Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2
Now, (m1v1)²/2m1 = (m2v2)²/2m2
∴(m1v1)/(m2v2) =
Then Ratio = √(2m2) : √(2m1)
Hope It Helps You!
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