Question

Two bodies of masses m1 and m2 have equal kinetic energy what is the ratio of their linear momentum

Answer 1

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~* THE ANSWER OF YOUR QUESTION IS..*~

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KINETIC ENERGY IN TERMS OF MOMENTUM=

K.E= P^2/2M

IF K.E1=K.E2

P1^2/2M1 = P2^2/2M2

SO.

. MI/ M2 = P1^2/P2^2

P1/P2=UNDERROOT M1/M2

HOPE IT WILL HELP YOU

Answer 2

Hey there!

Given,

Two bodies m1 and m2

Let the velocity of 1st body be = v1

Then its Kinetic energy = p²/2m1=(m1v1)²/2m2

Let the velocity of 2nd body be = v2

Then its Kinetic energy = p²/2m2 = (m2v2)²/2m2

Now, (m1v1)²/2m1 = (m2v2)²/2m2

 ∴(m1v1)/(m2v2) = $\frac{ \sqrt{2m2} }{ \sqrt{2m1} }$

Then Ratio = √(2m2) : √(2m1)

Hope It Helps You!